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Thread: Math Problem

  1. #1
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    So many of the people in the forum are strong mathematicians.

    Does anyone know how you solve for x in this equation?

    3^(4x) = 2^(2x+1)

  2. #2
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    34x = 22x+1

    2log(34x) = 2log(22x+1)

    4x.2log3 = 2x+1

    (4.2log3-2)x = 1

    x = 1/(4.2log3-2)

    where . is multiplication (usually indicated by a slightly raised dot)

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    [quote name='HansV' post='766155' date='19-Mar-2009 18:07']34x = 22x+1

    2log(34x) = 2log(22x+1)

    4x.2log3 = 2x+1

    (4.2log3-2)x = 1

    x = 1/(4.2log3-2)

    where . is multiplication (usually indicated by a slightly raised dot)[/quote]
    FWIW, In Excel parlance the formula is =1/(4*LOG(3,2)-2), which evaluates to 0.230422710309185
    Cheers,

    Paul Edstein
    [MS MVP - Word]

  4. #4
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    THANKS!!!

    [quote name='HansV' post='766155' date='19-Mar-2009 04:07']34x = 22x+1

    2log(34x) = 2log(22x+1)

    4x.2log3 = 2x+1

    (4.2log3-2)x = 1

    x = 1/(4.2log3-2)

    where . is multiplication (usually indicated by a slightly raised dot)[/quote]

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