Hi
I have been given the figures in columns A &B which tallies with my formula except row 5 which has been given a 100% which is correct please.
Regards
Braddy
Hi
I have been given the figures in columns A &B which tallies with my formula except row 5 which has been given a 100% which is correct please.
Regards
Braddy
If you are a fool at forty, you will always be a fool

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Hi Brad - Did you intend to include an example?
Tim
Hi Tim
Sorry about that now attached,
Regards
Braddy
If you are a fool at forty, you will always be a fool
Hi Tim
I was given these figures in hard copy and was trying to see if they are correct, ie the average number of burgalaries has increase by 100% from 2.7 to 5.3
Regards
Braddy
If you are a fool at forty, you will always be a fool
Braddy,
Disclaimer: I'm no mathematician!
That said try: =IF(A5>B5,(B5-A5)/ABS(A5),ABS(A5-B5)/ABS(A5))
I entered this one and got the correct answer: 96.30% 100% would = 5.4 {2.7 *2}.
I also dragged this formula up and down w/o appreciable changes in values.
The difference is in always dividing by the same column {A} for either increases or decreases.
Hi Braddy - The 2 formulas mentioned in previous posts above, produce essentially similar results. The differences between these 2 formulas are highlighted in pic below.
[attachment=89561:crime levels.jpg]
Hope that helps.
Hi Tim
Many thanks it was row 5 that concerned me, with your formula it is now correct @ 96.30% whereas mine resulted in 49.06%.
Thanks to all who replied.
Braddy![]()
If you are a fool at forty, you will always be a fool