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Thread: count unique dates

20110428, 17:11 #1
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count unique dates
I have a column with dates (A col) various people (B col) did tasks.
Sometimes a person does a task multiple times  could be twice in 1 day and once on three different other days. I want to be able to count that this person did the task FOUR times (four unique dates).
I don't want to use a filter or pivot table. Is there a formula that could calculate this for each person found in the B column?
I would have a list of the unique people on another sheet and want the corresponding count next to their name.
Thanks in advance.

20110428, 18:28 #2
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Could you attach a sample file showing your setup?
Steve

20110428, 18:38 #3
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sample.
Here's a sample.

20110429, 03:11 #4
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I can't see how you can do it as a formula, but a macro would work. You then use a formula to call the macro and return the result, or run the macro and place the result in the currently selected cell.
cheers, Paul

20110429, 10:26 #5
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For the life of me, I couldn't come up with a formula either so ended up using a pivot table and referenced the results as needed. Phew.
Thanks for viewing this.

20110504, 13:09 #6
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Try this
Here is a whopper of an array formula that does what you want
{=SUM(IF(FREQUENCY(
MATCH((TRANSPOSE(IF((($A$2:A$14&B$2:B$14)=($A$2:$A $14&D2)),($A$2:A$14&B$2:B$14),0))),
(TRANSPOSE(IF((($A$2:A$14&B$2:B$14)=($A$2:$A$14&D2 )),($A$2:A$14&B$2:B$14),0))),0),
MATCH((TRANSPOSE(IF((($A$2:A$14&B$2:B$14)=($A$2:$A $14&D2)),($A$2:A$14&B$2:B$14),0))),
(TRANSPOSE(IF((($A$2:A$14&B$2:B$14)=($A$2:$A$14&D2 )),($A$2:A$14&B$2:B$14),0))),0))
>0,1))1}
I've broken it up into multiple lines for easier reading[b]Catharine Richardson (WebGenii)
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20110504, 17:57 #7
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If you can stand a intermediate column (may be hidden), in C2 enter:
=1/SUMPRODUCT(($B$2:$B$14=B2)*($A$2:$A$14=A2))
Copy from C2 and paste to C3:C14
Then in E2:
=SUMIF($B$2:$B$14,D2,$C$2:$C$14)
Copy from E2 to E3:E6
Steve

20110505, 11:23 #8
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Steve
I was hoping you'd look at my honkin' formula and tell me  oh, this is how you can reduce it to two lines. I'm always slightly uneasy when I produce such a gigantic formula, as it often means I've chosen an unnecessarily complicated solution.
Although in this case ...[b]Catharine Richardson (WebGenii)
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20110509, 08:07 #9
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=COUNT(1/FREQUENCY(IF($B$2:$B$14=D2,IF($A$2:$A$14<>"",$A$2: $A$14)),IF($B$2:$B$14=D2,IF($A$2:$A$14<>"",$A$2:$A $14))))
arrayentered, should do it.Regards,
Rory
Microsoft MVP  Excel

20110509, 11:56 #10
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I knew it!
[b]Catharine Richardson (WebGenii)
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