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Thread: Excel calculation order

20110515, 21:08 #1
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Excel calculation order
The math problem: (1/16)^(2/3) produces an error in Excel.
However, ((1/16)^2)^(1/3) does not.
Neither does: ((1/16)^(1/3))^2
Why is that?
Guess it's that 1/16 with the attempt to raise it to the 2/3 power or the positive 0.6666 power.
Those negatives just have a problem when intermixed in power problems.
Almost gives the impression the problem doesn't have a real solution, but it does actually.Last edited by kweaver; 20110515 at 21:12.

20110516, 07:06 #2
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I presume that the method for calculating whole number roots are different than fractional. I will make a leap and presume the fractional problem:
A=(1/16)^(2/3)
A=0.0625^0.66666666666666
lnA = ln(0.0625^0.66666666666666)
lnA = 0.66666666666666 * ln(0.0625)
ln(0.625) is undefined so is an error.....
I presume the 1/3 uses a different procedure (perhaps a builtin one) involving some type of series...
These are only speculations, I am not privy to the actual coding done in excel...
Steve
PS something to think about:
(1/16)^(1/2)
Is a complex (nonreal) number.
But using distribution manipulation like you do, excel can calculate it:
((1/16)^(2))^(1/4) = 0.25
But 0.25^2 does not equal 1/16...
Which indicates to me that your distributive recalculation is not always the same thing as the original. Your reordering may be changing the values....
The solution you get in those 2 calcs:
0.15749 ^ (3/2) = 1/16 not 1/16....Last edited by sdckapr; 20110516 at 11:33.

20110516, 08:48 #3
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Excel Order of Operations
Excel has a very definite order of operations as shown in the attached table. The best policy is to never depend on the default order but to control the order of operations using parenthesis with the inner most set of parenthesis being evaluated first and working outward.
The default order of operations is as shown in the table with operations at the same level being evaluated left to right.
Examples:
Where A1=1; A2=2; A3=3; A4=4
=A1(A2*(A3^A4)) This is the parenthesized version of the default order.
=1(2*(3^4))
=1(2*81)
=1162
=161
=(A3*A4)(A1*(A4^A2))
=(3*4)(1*(4^2))
=12(1*(16)
=1216
=4
=(A3*A4)((A1)*(A4^A2))
=(3*4)((1)*(4^2)
=12(1*16)
=12(16)
=28Last edited by RetiredGeek; 20110517 at 09:52. Reason: Fixed Type pointed out by Fred...Thanks
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20110517, 08:59 #4
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typo?
RetiredGeek
I think you have a typo in your first example where you do 3^4 and in the next line have 2*91. The following line does correctly show 162, which would be the result of 2*81 and 81=3^4.
But for any nonmath people reading your post (eg, my students), you might want to consider correcting that. Otherwise, I know I'll be getting answers like that.
Fred

20110517, 09:26 #5
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there are a few other quirks that one can show and they have nothing to do with Excel. These have to do when neg numbers are introduced where they shouldn't be.
For example: log bases are defined to be nonneg  the log bases correspond to the base of an exponential. That is log(base) of arg = exp where base is a nonneg number by definition; when considering the corresponding exponential representation, this becomes base^exp = arg where base is >0 and NE 1. This is because if base were allowed to be neg, then you'd have an oscillating function as the sign of the result alternates between plus and minus as exp changes between even and odd. Without this restriction, one could ask the question log(2)16 = ?. My students always say 4 since (2)^4 = 16 (a teacher's favorite trick log question).
Similarly log args are also nonneg as you observed in Steve's example, since a pos base raised to any exp is always pos.
Makes for nice continuous functions.
Another item using the property of exponents in fraction form that applies to the original example: sqrt(4^2) = (sqrt(4))^2. But if use 4, one gets sqrt(4^2) =4 which is NE to (sqrt(4))^2 = 4. Hence, the rules of exponents do not apply to neg numbers.

20110517, 09:53 #6
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May the Forces of good computing be with you!
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