Replacing a string with bold text

[jrb]

I've been looking for this solution, but evidently I can't get the syntax correct.

I have numerous tables in my document and I would like to do a find and replace to bold those occurences.

Example:
Table 3.1.
Table 3.2.
Table 4.1.
etc.

How can I bold the entire string from Table all the way to the period?

[RetiredGeek]

JRB,

What you need to do is search using a "Regular Expression".
Here's a Microsoft Article on Using Regular Expressions in Word.

Then remember to apply the Format option to the "Replace With".

[jrb]

Thank you very much RG for the point in the right direction.

I got this to work...

Find= <(Table) [0-9](\.)[\0-9](\.)
Replace= ^&

...but can't seem to grasp how to catch a double number.

Example: Table 4.12.

I could do

<(Table) [0-9](\.)[0-9][0-9](\.)

but this would catch the Table 4.12. and not the Table 3.1. so I would have to do two searches.

Any way to do one?

[RetiredGeek]

JRB,

I think this will do it for all combos: Find= <(Table) [0-9]{1,}(\.)[\0-9]{1,}(\.)

[jrb]

Yes it does the job quite well.

I had actually used this before you posted and it works well for my requirements also.

<(Table) [0-9](\.)[\0-9]{1,2}(\.)

Much appreciated.