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Thread: formula needed for excel

20160521, 14:32 #1
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formula needed for excel
Hello All,
I have a need to solve for x
9,798 4.2% = x
6,813 4.2% = x
15,500 2.5% = x
10,908 1.9% = x
14,389 3.0% = x
8,950 4.3% = x
19,341 7.2% = x
12,82 10.6% = x
if the % is not showing it will be greater than 100 % to x ..(ie) 104.2%
is there a formula i can use down a column to achieve this goal?
Thank you for the help

20160521, 16:36 #2
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i'm not sure i follow what your meaning here

20160521, 16:47 #3
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first column ... current sales % is growth or decline from last year ... I am trying to find out what last years sales dollars are.

20160521, 17:02 #4
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ahhhh, so
x is a dollar figure
and you basically want the percentage increase (or decrease) in a hard cash dollar figure
ok, be back in a bit

20160521, 17:14 #5
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If you want the line by line increase or decrease, first separate the data into two columns, then multiply.
If there's something else you're looking for, please indicate.
Note: your last number is missing a digit.
Clip0015.jpg
Or did you want the result of the increase or decrease?
Clip0017.jpgLast edited by kweaver; 20160521 at 17:20.

20160521, 17:31 #6
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cvbs,
In this example, enter the formula:
=A2/(100%+B2)
In cell C2 then copy down. Hope I understood you correctly,
Maud
CVBS.png

20160521, 17:32 #7
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ok, so, first figure is this years sales, and the percentage is the over or under last years totals, then to find last years totals, try what i have done in this workbook, it might help
The ROUND function can be specified to go up or down (ROUNDUP / ROUNDDOWN) without defining it, it goes to the closest 10 i think
Formula
Code:=ROUNDUP(A1(A1*B1%),2)
workbook with some formatting to tidy the cell display....Last edited by Gunslinger; 20160521 at 17:54.

20160521, 18:20 #8
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Maud, I was unclear if the OP wanted the increase/decrease as I did or what you did. Either way, the OP has the solution!

20160521, 21:27 #9
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Kw,
I was unclear to me as well. But having a dilemma looked at from different angles often offers many creative solutions.
Maud