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Thread: Round and Round

  1. #1
    Silver Lounger
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    Round and Round

    In the diagram below, the "x" should be replaced by a certain number...
    - Ricky

  2. #2
    Plutonium Lounger
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    Re: Round and Round

    A memory puzzle ...
    <span style="background-color: #FFFF00; color: #FFFF00; font-weight: bold">x = 2</span hide>

  3. #3
    Silver Lounger
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    Re: Round and Round

    Ahhh! You remembered. Thought I'd try to sneak in an oldie. Anyway, right you are. <img src=/S/trophy.gif border=0 alt=trophy width=15 height=15>
    - Ricky

  4. #4
    Platinum Lounger
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    Re: Round and Round

    ...and I still can't remember how it is done...something to do with overlaps <img src=/S/sad.gif border=0 alt=sad width=15 height=15>
    Jerry

  5. #5
    Plutonium Lounger
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    Re: Round and Round

    See <post:=500,649>post 500,649</post:>.

  6. #6
    Platinum Lounger
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    Re: Round and Round

    So in that case, I may have to disagree with your answer, if that is the definition, I make <span style="background-color: #FFFF00; color: #FFFF00; font-weight: bold">three as 1, 2 and 3 are in overlapped circles</span hide> <img src=/S/shrug.gif border=0 alt=shrug width=39 height=15>
    Jerry

  7. #7
    Plutonium Lounger
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    Re: Round and Round

    If you apply Tony's description <span style="background-color: #FFFF00; color: #FFFF00; font-weight: bold">Each circle has a number in the centre of it. That number is the count of how many other numbers appear in that particular circle</span hide> you will see that <span style="background-color: #FFFF00; color: #FFFF00; font-weight: bold">the circle with x in the middle contains two other numbers, namely 1 and 2. So x = 2.</span hide>

  8. #8
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    Re: Round and Round

    <img src=/S/blush.gif border=0 alt=blush width=15 height=15>
    Jerry

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