1. ## A little time-filler

1#
P is to L.
M is to OK.
Hence, D is to ___

2#
Amoebas reproduce by splitting in two. An amoeba which does so every minute is placed in a jar at exactly ten o`clock in the morning. At 12:00 noon the jar is full. At what time is the jar half full?

3#
Which of these letter combinations does NOT belong?

VBN
CVB
UIO
YGR
FGH

4#
The following group of numbers represents an 11-letter word. Can you figure out the word?

46244628466
31113211332

2. ## Re: A little time-filler

2# <span style="background-color: #FFFF00; color: #000000; font-weight: bold"><font color=yellow>Since the number of amoebas doubles every minute, the jar was half full at 11:59</font color=yellow></span hi>

3. ## Re: A little time-filler

3# <span style="background-color: #FFFF00; color: #000000; font-weight: bold"><font color=yellow>YGR is the only group that is not contiguous on a standard keyboard.</font color=yellow></span hi>

4. ## Re: A little time-filler

Correct on both counts.

5. ## Re: A little time-filler

1# 2 possible answers <span style="background-color: #FFFF00; color: #000000; font-weight: bold"><font color=yellow>RT or RTED</font color=yellow></span hi>

6. ## Re: A little time-filler

4# <span style="background-color: #FFFF00; color: #000000; font-weight: bold"><font color=yellow>In the age of text messaging, the word is IMAGINATION</font color=yellow></span hi>

7. ## Re: A little time-filler

2. There is not enough information provided to anser this question.

<span style="background-color: #FFFF00; color: #000000; font-weight: bold"><font color=yellow>When an amoeba splits in two, the two new amoeba have the same total mass as the original, and they need to grow before they can split again. At 11:59 there were half as many amoeba as at 12:00 but they were much bigger and the jar was very nearly full. </font color=yellow></span hi>

StuartR

8. ## Re: A little time-filler

Doubley correct, Tony.

9. ## Re: A little time-filler

Impeccable logic, Stuart. The missing information would be that they undergo binary fission when the daughters have grown to twice their original size.

10. ## Re: A little time-filler

In that case, I think the answer to 2 is <span style="background-color: #FFFF00; color: #000000; font-weight: bold"><font color=yellow> 11:59am </font color=yellow></span hi>, but I'm really not sure.

StuartR

11. ## Re: A little time-filler

I thought so too, but since your response, I'm not sure either.

12. ## Re: A little time-filler

I would agree.
On the assumption that all things are equal and that they multiply and grow consistently each minute, then it will be one minute before 12:00.
Or perhaps the answer is, (the period of time it takes from splitting into two until they regain their original size) before 12:00. However, if by some freak of nature on splitting into two, the sum of two parts volume is less than the volume of one before it split, there would be two answers.
Or something.

13. ## Re: A little time-filler

Good point. It seems likely that the sum of the volumes of the daughters will be less than the volume of the parent.

14. ## Re: A little time-filler

Hmmm... by my calculations <span style="background-color: #FFFF00; color: #000000; font-weight: bold"><font color=yellow>at 11:59 it would be half empty.</font color=yellow></span hi> <img src=/S/grin.gif border=0 alt=grin width=15 height=15>

Alan